How Was The Group Of Horses Divided Among the 3 Sons?
Wear your logical hats and try to solve this riddle. This is a tough one, only 2 % people who attempt this puzzle get the correct explanation.
An old farmer had 3 sons and 17 horses.
When he died his will was read in the village meeting.
According to the will, the oldest son was to get half of the horses, the middle was to get one third of the horses and the youngest son was to get one ninth of the horses.
None of the villagers were able to divide the horses as the result was coming in fractions.
The sons started fighting on how to divide the horses and did not reach any agreement.
A traveling mathematician rode a horse to the village meeting at this point.
He heard the problem at hand and proposed a solution with which all the sons got their share in the property without harming any animal.
What was the solution and how was the group of horses divided?
So were you able to solve the riddle? Leave your answers in the comment section below.
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Answer & Explanation:
The mathematician’s advice was to add his horse to the group of horses, to make a total of 18 horses.
So with the addition horse now the division of horses became simple.
The oldest son would get half of the horses i.e. 9 horses.
The middle son would get one third, so 6 horses
The youngest son would get one ninth, that is 2 horses
There is now 1 remaining horse which belongs to the traveling mathematician.
See more: Many Adults Are Stumped By The Horse Riddle – Can You Solve It?
A man buys a horse for $60. He sells it for $70.
He then buys the horse back for $80. And he sells the horse for $90.
In the end, how much money did the man make or lose? Or did he break even?
Many people are unable to figure out the correct answer. Can you? Watch the video for a solution.
Answer To Buying And Selling A Horse Riddle
The short answer is the man profited $20. The man makes $10 each of the two times he sells the horse, for a profit of $20.
The answer can be verified by accounting for what the man has in each transaction.
Step 1: buys a horse for $60. The man is -$60 of cash from his starting point.
Step 2: sells the horse for $70. The man gets $70, so he is a net -$60 + $70 = $10 of cash.
Step 3: buys the horse for $80. The man spends $80, which means he is a net of $10 – $80 = -$70 cash.
Step 4: sells the horse for $90. The man gets $90, which means he is a net of -$70 + $90 = $20 cash.
In the end the man has $20 more than he started with.
(Update 12/23) Why were people confused?
I received a request to elaborate common errors for solving the problem. Generally it seems people were confused about which numbers to add/subtract, and also people got confused since it was the same horse in each transaction. If the first sale and second sale were for different items then people had no trouble–that’s probably a good example of a mental bias and a way to correct the bias.
In particular, people came up with answers of “broke even” and “gained $10.” The “broke even” appears to be because people lost track of numbers, or did not know which numbers to add and subtract (for example 60 + 90 – 80 – 70 = 0). The “gained $10” comes from the fact the person gained $10 in the first sale. But then to buy the horse for $80, the person only has $70 and needs to borrow $10–making the person even. After the sale at $90 the person nets $10 and gains $10. The mistake here is accounting only after the first sale–the person does gain $10 after the second sale, and this adds to the $10 from the first sale.
See more: People Are Losing Their Shit Over This Viral Riddle! Can You Solve It?